Summary
COSEL Power Supply, Noise Filter 2025 Product Catalog
AME seriesDefinition of load factor!Defi nition of load factorLoad [%] = The largest value of A 0 , A 11 - A 626A 0 =(Sum of each module power)Σk=1 (I k1×V k1 +I k2×V k2 )×100=(Total output power)(Total output power)×100A 11 , A 21 , A 31 , A 41 , A 51 , A 61 : AK 1 =I K1 /I OK1×100A 12 , A 22 , A 32 , A 42 , A 52 , A 62 : AK 2 =I K1 /I OK2×100I K1 , V K1 , I OK1 : output current, voltage, and rated current except for V2 in module RI K2 , V K2 , I OK2 : output current, voltage, and rated current for V2 in module RTotal output power : Dependent upon input voltageSuffi x k means the k-th slot¶If you use the module that apply peak current at the peak current,“I K1”is calculated by peak current.When Calcurating load factor of module,“I K1”is calcurated by average current.A method of use peak current, Refer to 4 Peak in Instruction Manual!Usage example[Example1] Method to confi rm that AM04-RDBA-0000 can be used under the following conditions.Input voltage : 100VAC Ambient temperature : 50COutput model : slot1 : 5V 12A slot2 : 5V 12A slot3 : 48V 1A slot4 : 24V 2A, 24V 1AAccording to the“Derating curve for input voltage”, total output power is 250W.Clculating A 11 - A 42A 0 =(5×12+12×5+48×1+24×2+24×1)/250×100=241.2/250×100=96%A 11 =12/12×100=100%A 21 =5/8.5×100=59%A 31 =1/2.5×100=40%A 41 =2/3×100=67%A 42 =1/3×100=34%Accordingly, because the“Derating curve for ambient temperature”indicates that up to 100% of the maximum load can be used up to 50Cand the largest value amongst A 0 , A 11 , A 21 , A 31 , A 41 , and A 42 is 100%, this assures that these input and output conditions are acceptable.AME[Example 2] Method to confi rm that AM12-RHGFFE-0000 can be used under the following conditions.Input voltage : 200VAC Ambient temperature : 50COutput model : slot1 : 5V 32A slot2 : 12V 16A slot3 : 12V 10A slot4 : 24V 8A (peak 15A) slot5 : 48V 4Aslot6 : 24V 2.5A, 24V 2.5AAccording to the“Derating curve for input voltage”, total output power is 1200W.Clculating A 11 - A 62A 0 =(5×32+12×16+12×10+24×15+48×4+24×2.5+24×2.5)/1200×100=1144/1200×100=96%A 11 =32/32×100=100%A 21 =16/20×100=80%A 31 =10/20×100=50%A 41 =8/10×100=80%A 51 =4/5×100=80%A 61 =2.5/3×100=84%A 62 =2.5/3×100=84%Accordingly, because the“Derating curve for ambient temperature”indicates that up to 100% of the maximum load can be used up to 50Cand the largest value A 0 , A 11 , A 21 , A 31 , A 41 , A 51 , A 61 and A 62 is 96%, this assures that these input and output conditions are acceptable.AME-10 ? 600 ?